Timeline for The cone on a manifold
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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May 1, 2017 at 19:38 | history | edited | Ben McKay | CC BY-SA 3.0 |
clarified the smooth structure
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Dec 6, 2015 at 12:34 | history | edited | Ben McKay | CC BY-SA 3.0 |
Corrected spelling
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Mar 3, 2015 at 19:53 | history | edited | Ricardo Andrade |
added missing top-level tag
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S Mar 3, 2015 at 19:00 | history | suggested | Ali Taghavi |
I add a tag
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Mar 3, 2015 at 18:59 | review | Suggested edits | |||
S Mar 3, 2015 at 19:00 | |||||
Nov 3, 2013 at 12:33 | comment | added | Ryan Budney | Without the Poincare conjecture you can say $X$ is a homotopy-sphere, that's what your argument gives you. | |
Nov 3, 2013 at 12:29 | history | edited | Ben McKay | CC BY-SA 3.0 |
added 30 characters in body
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Nov 1, 2013 at 15:43 | comment | added | Sam | @shu : I doubt it. | |
Nov 1, 2013 at 15:42 | comment | added | shu | @sam, you are right I forgot it. But is there a proof without using Poincare conjecture? | |
Nov 1, 2013 at 15:31 | comment | added | Sam | @shu : The Poincare conjecture also requires $X$ to be simply-connected. | |
Nov 1, 2013 at 15:30 | answer | added | Sam | timeline score: 24 | |
Nov 1, 2013 at 14:54 | comment | added | shu | if $CX$ is smooth, the intersection homology will egale to singular homology. Hence, all the Betti number of $X$ is 0 except the 0 and top degree. Thus...by Poincare conjecture, $X$ is a sphere. But I think there should be a simple argument. | |
Nov 1, 2013 at 14:04 | history | asked | Ben McKay | CC BY-SA 3.0 |