Timeline for Subgroups of finite reflection groups that do not fix a point
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 22, 2013 at 16:26 | comment | added | Nathan Reading | What do you mean by the "rank" of a subgroup? For example, what is the rank of the alternating group inside the symmetric group? Are you considering only certain special subgroups, like parabolic subgroups? A parabolic subgroup has a well-defined rank, but other subgroups? (My apologies if there is some general definition of rank that I don't know.) | |
| Nov 18, 2013 at 12:58 | vote | accept | Tom | ||
| Nov 5, 2013 at 8:22 | vote | accept | Tom | ||
| Nov 5, 2013 at 8:22 | |||||
| Nov 5, 2013 at 8:22 | comment | added | Tom | No I am a bit confused specially by the "answer" of Ben. | |
| Nov 4, 2013 at 19:39 | comment | added | Misha | Tom: There are other possibilities too. Consider do instance what happens in rank 2 cases. | |
| Nov 4, 2013 at 19:03 | answer | added | Ben | timeline score: 0 | |
| Nov 4, 2013 at 12:38 | comment | added | Tom | If $s_1$ to $s_n$ are the roots and $s_1$ is the root which fixes $x$ then the group generated by $s_2$ to $s_n$ would be what I need. However, is this all that can happen? | |
| Nov 4, 2013 at 9:01 | comment | added | Tom | yes, that is what I mean | |
| Nov 2, 2013 at 0:42 | comment | added | S. Carnahan♦ | When you say "do not stabilize" do you mean that the stabilizer of $x$ in the subgroup is trivial? | |
| Nov 1, 2013 at 15:02 | history | edited | Tom | CC BY-SA 3.0 |
added 3 characters in body
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| Nov 1, 2013 at 12:20 | history | asked | Tom | CC BY-SA 3.0 |