Timeline for zero homology of augmented Koszul complex implies the sequence is regular?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 15, 2013 at 21:15 | vote | accept | Manos | ||
| Nov 15, 2013 at 21:15 | vote | accept | Manos | ||
| Nov 15, 2013 at 21:15 | |||||
| Nov 4, 2013 at 22:28 | comment | added | user26857 | @Manos Sorry, I've thought that $I=(x(y-1),z(y-1))$. Please read my comment using this notation. | |
| Nov 4, 2013 at 22:04 | comment | added | Manos | @YACP: Since $y \in I$ we have $I+yR=I$. Is there a typo in your comment? | |
| Nov 4, 2013 at 16:20 | comment | added | user26857 | +1. Your example was the first that crossed my mind too (as a counterexample to Manos' question) since it is known as having a bad behaviour with respect to grade, that is, grade of $I$ is 1 while the grade of $I+yR$ is 3. | |
| Nov 1, 2013 at 17:56 | history | edited | Youngsu | CC BY-SA 3.0 |
added 1 characters in body
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| Nov 1, 2013 at 17:55 | comment | added | Youngsu | @Manos: I see I thought the statement highlinted was Theorem 16.8. Let me change theorem to corollary. | |
| Nov 1, 2013 at 15:14 | comment | added | Manos | The point of debate is the Corollary to Theorem 16.8. The theorem itself is fine. | |
| Nov 1, 2013 at 0:10 | history | answered | Youngsu | CC BY-SA 3.0 |