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Oct 31, 2013 at 5:08 comment added Mohammad Golshani Your answer is really interesting.
Oct 30, 2013 at 18:55 comment added Joel David Hamkins I have edited .
Oct 30, 2013 at 18:55 history edited Joel David Hamkins CC BY-SA 3.0
added 410 characters in body
Oct 30, 2013 at 15:52 comment added Joel David Hamkins You are right; I'll edit.
Oct 30, 2013 at 15:48 comment added Mohammad Golshani In fact I had the idea building $\omega-$many stationary classes, the intersection of any finitely many of them stationary, but their full intersection empty, and then use club forcing to get the desired result, but I didn't know how to figure it.
Oct 30, 2013 at 15:45 comment added Mohammad Golshani I think your stationary sets should be fat stationary.
Oct 30, 2013 at 15:13 vote accept CommunityBot
Oct 30, 2013 at 13:52 history answered Joel David Hamkins CC BY-SA 3.0