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Oct 29, 2013 at 19:04 vote accept Manuel Bärenz
Oct 29, 2013 at 19:04 comment added Manuel Bärenz Ah, if one takes the braiding present in $\mathcal{C}$ then all the morphisms in $\mathcal{C}$ satisfy the condition, by the axioms of a braided category. Thanks!
Oct 29, 2013 at 18:47 comment added Manuel Bärenz How does this inclusion work? What is the canonical choice of half braiding $\phi: - \otimes X \To X \otimes -$ for a given object $X$? But only the morphisms that commute with the half braiding appear in the Drinfeld centre, right? So how is this an inclusion?
Oct 29, 2013 at 18:08 history answered Evan Jenkins CC BY-SA 3.0