Timeline for Subset of Spec(A) realized as inverse image of some Spec(B)
Current License: CC BY-SA 3.0
4 events
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Oct 30, 2013 at 12:44 | comment | added | Cantlog | One can also take $A=\mathbb Q$, $B=\mathbb Q(t)$ and $B'=\overline{\mathbb Q}$, in which case there is no morphism between $B$ and $B'$ from either sides. | |
Oct 28, 2013 at 15:22 | history | edited | Julian Rosen | CC BY-SA 3.0 |
added 17 characters in body
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Oct 28, 2013 at 15:16 | history | edited | Julian Rosen | CC BY-SA 3.0 |
added 17 characters in body
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Oct 28, 2013 at 15:11 | history | answered | Julian Rosen | CC BY-SA 3.0 |