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Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some given positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$ for an arbitrary $k$?

  2. For an arbitrary $k$, when is the solution $G_2$ a non-negative matrix?

Thanks

Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some given positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$ for an arbitrary $k$?

  2. For an arbitrary $k$, when is the solution $G_2$ non-negative?

Thanks

Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some given positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$ for an arbitrary $k$?

  2. For an arbitrary $k$, when is the solution $G_2$ a non-negative matrix?

Thanks

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Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some given positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$ for an arbitrary $k$?

  2. WhenFor an arbitrary $k$, when is the solution $G_2$ non-negative?

Thanks

Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$?

  2. When is $G_2$ non-negative?

Thanks

Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some given positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$ for an arbitrary $k$?

  2. For an arbitrary $k$, when is the solution $G_2$ non-negative?

Thanks

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Let $diag_k(Z)$, where $Z$ is a matrix be a matrix ofsquare matrix; denote by $\text{diag}_k(Z)$ the same size holdingmatrix containing the center $2k+1$ diagonals of $Z$ and zeros elsewhere,; i.e., if $T=diag_k(Z$$T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and} T_{ij}=0 \; \mathrm{otherwise}.$$$$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Now, letLet $G_1$ be any non-negativea nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some positive $\lambda$. Let Let $G_2$ be ana Hermitian matrix that satisfies $G_2=diag_k(G_2)$$G_2=\text{diag}_k(G_2)$ for some $k$, and definelet $X_2=(G_1+I)^{-1}$$X_2=(G_2+I)^{-1}$ be such that satisfies $$diag_k(X_1)=diag_k(X_2).$$$$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$?

  2. When is $G_2$ non-negative?

Thanks

Let $diag_k(Z)$, where $Z$ is a matrix be a matrix of the same size holding the center $2k+1$ diagonals of $Z$ and zeros elsewhere, i.e. if $T=diag_k(Z$ then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and} T_{ij}=0 \; \mathrm{otherwise}.$$

Now, let $G_1$ be any non-negative Hermitian matrix and construct $X_1=(G_1+\lambda I)^{-1}$ for some positive $\lambda$. Let $G_2$ be an Hermitian matrix that satisfies $G_2=diag_k(G_2)$ for some $k$, and define $X_2=(G_1+I)^{-1}$ that satisfies $$diag_k(X_1)=diag_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$?

  2. When is $G_2$ non-negative?

Thanks

Let $Z$ be a square matrix; denote by $\text{diag}_k(Z)$ the matrix containing the center $2k+1$ diagonals of $Z$; i.e., if $T=\text{diag}_k(Z)$, then $$T_{ij}=Z_{ij}, \;\mathrm{if}\; |i-j|\leq k, \mathrm{and }\ T_{ij}=0 \; \mathrm{otherwise}.$$

Let $G_1$ be a nonnegative Hermitian matrix, and construct $X_1=(G_1+\lambda I)^{-1}$ for some positive $\lambda$. Let $G_2$ be a Hermitian matrix that satisfies $G_2=\text{diag}_k(G_2)$ for some $k$, and let $X_2=(G_2+I)^{-1}$ be such that $$\text{diag}_k(X_1)=\text{diag}_k(X_2).$$

Two questions:

  1. Is there any closed form for $G_2$?

  2. When is $G_2$ non-negative?

Thanks

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