Timeline for Solving a quadratic equation for an hermitian matrix
Current License: CC BY-SA 3.0
3 events
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| Jun 24, 2014 at 14:29 | comment | added | loup blanc | @Robert Bryant, a problem of glasses ? I wrote ``$S$ must have the spectrum of a real matrix'', that is $S$ must have real or pairwise conjugate eigenvalues. Never I say that this is a sufficient condition. | |
| Jun 24, 2014 at 12:55 | comment | added | Robert Bryant | It is not true that $S$ having real eigenvalues and being invertible is sufficient for there to be a solution. As I point out in my answer, when $n=2$, there is no solution when $S$ has two distinct real, nonzero eigenvalues if at least one of them is negative. | |
| Oct 24, 2013 at 17:05 | history | answered | loup blanc | CC BY-SA 3.0 |