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Feb 8, 2010 at 5:43 comment added Emerton Dear Bjorn, Yes!
Feb 8, 2010 at 5:25 comment added Bjorn Poonen Restatement: Let G' be the image of G acting by left translation on the set of left cosets of N in G. (Excuse my use of the C-word!) Amusingly, when N is a non-normal subgroup, this produces the quotient by the largest normal subgroup contained in N, whereas (as remarked by Tom Church) the unknown/Brandenberg/Poonen construction produces the quotient by the smallest normal subgroup containing N.
Feb 8, 2010 at 0:59 comment added Martin Brandenburg this is exactly what I've been looking for! I don't see how the universal property can be verified directly from the construction (perhaps anybody else?), but for me it's sufficient that $p : G \to G'$ is a surjektive homomorphism with kernel exactly $N$.
Feb 8, 2010 at 0:58 vote accept Martin Brandenburg
Feb 7, 2010 at 21:04 history answered Emerton CC BY-SA 2.5