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Oct 23, 2013 at 7:30 vote accept Lior Eldar
Oct 22, 2013 at 13:03 answer added Carlo Beenakker timeline score: 2
Oct 22, 2013 at 12:22 comment added Lior Eldar Thanks for the comment. Please check out modified question.
Oct 22, 2013 at 12:22 history edited Lior Eldar CC BY-SA 3.0
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Oct 22, 2013 at 9:41 comment added Carlo Beenakker independent eigenvalues --- no: there is no way to avoid eigenvalue repulsion; in particular, take $A=0$, then the eigenvalues of $A+G$ are those of $G$, which show a linear repulsion (Gaussian Orthogonal Ensemble)
Oct 22, 2013 at 8:03 history asked Lior Eldar CC BY-SA 3.0