Timeline for Finite generation of a commutative algebra via its quotients
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 21, 2013 at 18:09 | comment | added | Mohan | Take $\mathbb{C}[t]$ and invert all polynomials whose roots are not integers. This is not finitely generated and has the dimension of all quotients by $t-n$, $n$ an integer equals one. | |
| Oct 21, 2013 at 14:51 | answer | added | Qiaochu Yuan | timeline score: 4 | |
| Oct 21, 2013 at 14:44 | review | First posts | |||
| Oct 21, 2013 at 14:44 | |||||
| Oct 21, 2013 at 14:26 | history | asked | Ehud Meir | CC BY-SA 3.0 |