Timeline for When does a group action on a k-algebra induce an algebraic action on the spectrum?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2013 at 10:11 | vote | accept | Jesko Hüttenhain | ||
| Oct 18, 2013 at 10:11 | comment | added | Jesko Hüttenhain | That looks great! Thanks a lot. I'd be really thankful if you could also see to my comment over there. | |
| Oct 17, 2013 at 13:36 | comment | added | David E Speyer | I agree, the currently selected answer doesn't work. Did you look at the second half of the answer I left there? | |
| Oct 17, 2013 at 5:17 | comment | added | Jesko Hüttenhain | But then, the anwswer to my previous question would not work at all, because simply talking about actions on the coordinate rings will not give you an algebraic action on the varieties. At least in that very special case where $A$ is integral over some ring $R$ and the restricted action is algebraic, will it work? | |
| Oct 16, 2013 at 22:36 | history | edited | David E Speyer | CC BY-SA 3.0 |
added 726 characters in body
|
| Oct 16, 2013 at 22:33 | comment | added | David E Speyer | Looking back at your motivating question, I agree. The problem there is getting a map of schemes in the first place. | |
| Oct 16, 2013 at 22:01 | comment | added | Jesko Hüttenhain | Oh, hm, actually I think that I have a map $G(k)\times X(k)\to X(k)$ of sets, and I am wondering if it comes from a morphism $G\times X\to X$ of schemes. | |
| Oct 16, 2013 at 19:45 | history | edited | David E Speyer | CC BY-SA 3.0 |
deleted 14 characters in body
|
| Oct 16, 2013 at 19:31 | history | edited | David E Speyer | CC BY-SA 3.0 |
deleted 1873 characters in body
|
| Oct 16, 2013 at 19:23 | history | answered | David E Speyer | CC BY-SA 3.0 |