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Oct 23, 2013 at 17:04 comment added Puzzled If X is projective and two general points can be connected by a rational curve then any two points can be connected by a rational curve.
Oct 16, 2013 at 21:10 comment added HNuer I acknowledged, after Jack's comments above, that your proof works for the usual definition of rationally connected, namely that two general points can be connected by a rational curve. However, I edited the question to more clearly reflect what I was asking which was why ANY two points can be connected by a chain of rational curves.
Oct 16, 2013 at 17:03 comment added Puzzled Yes, $\phi_{|L}$ is a morphism just because $L$ is a smooth curve. I am assuming $X$ projective.
Oct 16, 2013 at 16:54 comment added Sándor Kovács @Scott: $L$ is a smooth projective curve. There is no room for indeterminacy. (I suppose one may assume that $X$ is projective as well).
Oct 16, 2013 at 15:46 comment added S. Carnahan Why is $\phi|_L$ a morphism instead of a rational map?
Oct 16, 2013 at 13:40 history answered Puzzled CC BY-SA 3.0