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Feb 13, 2010 at 16:12 history edited Pandelis Dodos CC BY-SA 2.5
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Feb 7, 2010 at 19:11 comment added Pandelis Dodos Ady, if you do the coloring argument then you will "canonize" the function $F$, i.e. $F(x)$ will only depend of the size of the support of $x$. I thought that this was enough to "freeze" the values of $F$ on a large set and this was wrong. What the coloring argument yielded was a hint in order to get the counterexample above. For "bigger" spaces I honestly don't know.
Feb 7, 2010 at 15:07 comment added Ady @Pandelis Why it [i.e., the "colouring" argument] is not correct ? At least, do yo have an affirmative result for some "big" spaces ?
Feb 7, 2010 at 12:17 history answered Pandelis Dodos CC BY-SA 2.5