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Oct 15, 2013 at 17:09 comment added Anonymous I see the problem now, thank you very much!
Oct 15, 2013 at 16:24 vote accept Anonymous
Oct 15, 2013 at 16:21 comment added Andy Putman @yanglee : For your first question, see any standard source on the mapping class group (eg Farb-Margalit). For your second question, try to write down a careful construction of your inclusion and you will see that it is not well-defined even though it is well-defined on Dehn twists.
Oct 15, 2013 at 13:19 comment added Anonymous I am sorry, but there a still a couple of things I still don't get. I'll write here, there may be naive mistakes, please correct me if I am wrong. $PMCG(S_g^b)$ is generated by Dehn twists around non-trivial simple closed curves, right? Every non-trivial simple closed of $S_g^b$ can be seen as a non-trivial simple closed curve in $S_{g,b}$, so it seems that $PMCG(S_g^b)$ is "naturally" a subgroup of $PMCG(S_{g,b})$. So why does the inclusion $PMCG(S_{g}^b) \to PMCG(S_{g,b})$ not split the sequence above? Thank you in advance.
Oct 15, 2013 at 13:18 comment added Anonymous Thank you for your answer. Could you clarify your point about abelianizations and precise why the abelianization of $PMCG(S_{g,b})$ is trivial?
Oct 15, 2013 at 3:29 history edited Andy Putman CC BY-SA 3.0
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Oct 15, 2013 at 3:22 history answered Andy Putman CC BY-SA 3.0