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Oct 16, 2013 at 14:44 comment added Peter Mueller @joro: I think you should work that out on your own -- and accept the answer once you checked if it is correct.
Oct 16, 2013 at 5:01 comment added joro Thanks. Are the known points the only ones your transformations lose? (The original curve has points).
Oct 15, 2013 at 14:41 history edited Abhinav Kumar CC BY-SA 3.0
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Oct 15, 2013 at 14:17 comment added Peter Mueller Indeed, the left hand side vanishes in the two points $(h,t)=(1/2+\alpha/6, 3+\alpha)$ with $\alpha=\pm\sqrt{3}$, and seems to be positive elsewhere.
Oct 15, 2013 at 6:53 comment added Michael Zieve Does this have any real points? The left side was positive for the first several pairs $(h,t)$ I tried.
Oct 14, 2013 at 20:30 history answered Abhinav Kumar CC BY-SA 3.0