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Oct 15, 2013 at 14:50 history edited yangyang CC BY-SA 3.0
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Oct 12, 2013 at 21:27 comment added Bombyx mori @yangyang: Yes, they has to commute. You can write out local trivilizations and this become $g(\phi(e))=\phi(g(e))$, which means $g$' action does not depend on the charts.
Oct 12, 2013 at 13:36 answer added Peter May timeline score: 2
Oct 12, 2013 at 12:12 comment added Tom Goodwillie Also beware that "equivariant bundle" often means a bundle in which $G$ acts on both $E$ and $B$, compatibly.
Oct 12, 2013 at 12:11 comment added Tom Goodwillie Beware of the phrase "the fibre". There is not a canonical action of $GL(R^k)$ on each fibre of a rank $k$ vector bundle.
Oct 12, 2013 at 12:03 history asked yangyang CC BY-SA 3.0