Timeline for Why is addition of observables in quantum mechanics commutative?
Current License: CC BY-SA 2.5
6 events
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| Feb 9, 2010 at 21:17 | comment | added | Tetis - Gianmarco Bramanti | @AF I think the points "touching" the very interesting question you pointed out are two: the choice of a algebra structure for operator is IMHO based on both: conservative approach with regard to the construction of quantum mechanics ( in order to safe a predictive theory, so that the effect of measure in the state of universe was at first neglected at all) an empiric base with respect to the measure of quantum quantities corresponding to additive classical quantities. E.g. the energies and spin components. Anyway in old QM these were partly "theorems" nowadays, at all, definitions. | |
| Feb 9, 2010 at 20:59 | comment | added | Tetis - Gianmarco Bramanti | @ YC sure you can edit it, I'm sure there are a lot of mistaken. Thanks in advance. | |
| Feb 8, 2010 at 19:56 | comment | added | Andrea Ferretti | It looks very interesting indeed, but sadly it does not touch in any way the original question. | |
| Feb 7, 2010 at 0:14 | comment | added | Yemon Choi | This looks very interesting and covers a lot of ground. Would you object if I made some small edits for language? | |
| Feb 7, 2010 at 0:08 | history | edited | Tetis - Gianmarco Bramanti | CC BY-SA 2.5 |
I correct something and integrate some part of the old text.
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| Feb 6, 2010 at 23:10 | history | answered | Tetis - Gianmarco Bramanti | CC BY-SA 2.5 |