Timeline for Conjugacy classes of PGL(3,Z)
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Oct 9, 2013 at 19:44 | comment | added | YCor | yes because the obvious homomorphism $SL_3(\mathbb{Z})\to PGL_3(\mathbb{Z})$ is an isomorphism | |
Oct 9, 2013 at 19:11 | comment | added | tj_ | @Yves: Thanks for pointing out that $GL_3(\mathbb{Z}) \not\cong PGL_3(\mathbb{Z})$. I understand $GL_3(\mathbb{Z}) \cong SL_3(\mathbb{Z})\times \lbrace \pm 1\rbrace$. But do we really have $GL_3(\mathbb{Z}) \cong PGL_3(\mathbb{Z}) \times \lbrace \pm 1\rbrace$ ? | |
Oct 9, 2013 at 19:03 | history | edited | tj_ | CC BY-SA 3.0 |
Added the case PGL_3(Z)
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Oct 9, 2013 at 17:44 | comment | added | YCor | @tj: no, $GL_3(\mathbb{Z})$ is not isomorphic to $PGL_3(\mathbb{Z})$, but to $PGL_3(\mathbb{Z})\times\{\pm 1\}$. | |
Oct 9, 2013 at 16:03 | history | answered | tj_ | CC BY-SA 3.0 |