Timeline for On matrices conjugated in a faithful representation
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Oct 11, 2013 at 4:36 | answer | added | S. Carnahan♦ | timeline score: 1 | |
| Oct 10, 2013 at 12:12 | comment | added | prochet | yes but it doesn't imply that the matrices are not conjugated. $g$ and $g_{1}$ are different. | |
| Oct 10, 2013 at 9:55 | comment | added | S. Carnahan♦ | I don't think your edit has fixed much. For example, $G$ could be $SL_2 \times SL_2$, embedded in $GL_4$, and you could conjugate by something in $GL_4$ that switches the two factors. | |
| Oct 10, 2013 at 8:08 | comment | added | Marc Palm | Ah okay, I wasn't seeing the algebraically closed field part. I was thinking about local fields. Still S.Carnahan's example applies, doesn't it? | |
| Oct 9, 2013 at 20:38 | history | edited | prochet | CC BY-SA 3.0 |
added 40 characters in body
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| Oct 9, 2013 at 20:35 | comment | added | prochet | it doesn't fail for $SL_{2}$ because if you have $g\in GL_{2}(O)$ that conjugates, then $\frac{1}{\lambda}g\in SL_{2}(O)$ where $\lambda=\sqrt\det(g)$ that exists because $k$ is algebraically closed. | |
| Oct 8, 2013 at 21:47 | comment | added | Marc Palm | I would prefer the question to be a comparison of the orbits... my naive idea is that more useful things can be said there. definitely the answer to the question in its current form is no. anyway +1. | |
| S Oct 8, 2013 at 13:05 | history | suggested | Michael Albanese | CC BY-SA 3.0 |
Fixed some typos and a little bit of grammar.
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| Oct 8, 2013 at 12:55 | review | Suggested edits | |||
| S Oct 8, 2013 at 13:05 | |||||
| Oct 8, 2013 at 9:24 | comment | added | Marc Palm | Even $SL(2)$ inside $GL(2)$ seem to fail. | |
| Oct 8, 2013 at 9:08 | comment | added | S. Carnahan♦ | Do any of your conditions prevent $G$ from being a torus? | |
| Oct 8, 2013 at 8:54 | history | asked | prochet | CC BY-SA 3.0 |