Timeline for Jack polynomials as determinants
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 14, 2019 at 4:32 | comment | added | Student | At $\alpha=1$, can Jacobi-Trudi be explained as a result that follow from consideration of differential operators and eigenfunctions? | |
| Feb 13, 2010 at 18:40 | vote | accept | Sasha | ||
| Feb 9, 2010 at 1:30 | comment | added | Pavel Etingof | There is no difference whatsoever between the classical and quantum case. Just set q=1 and use usual Lie algebras instead of quantum groups. The arguments apply verbatim. | |
| Feb 8, 2010 at 22:57 | comment | added | Sasha | Pavel, thank you very much for your answer. Unfortunatelly "Quantum" q-deformed polynomials are too involved for me, and, though in the classical limit relation you told me about could give one of the required formulas,I would prefer to have an "classical" explanation in terms like Calogero-Sutherland operator you mention. | |
| Feb 6, 2010 at 14:41 | history | edited | Pavel Etingof | CC BY-SA 2.5 |
added reference to formula
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| Feb 6, 2010 at 14:31 | history | answered | Pavel Etingof | CC BY-SA 2.5 |