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S Oct 17, 2013 at 21:31 history bounty ended James Propp
S Oct 17, 2013 at 21:31 history notice removed James Propp
Oct 17, 2013 at 21:29 vote accept James Propp
Oct 16, 2013 at 14:59 answer added Dimitri timeline score: 4
Oct 16, 2013 at 10:48 comment added user25199 Maybe not generic, but $n=3$ is just given by the usual Soddy formula. Note that there are two relations - both $r_−$ and $r_+$ are determined by the others, which are free. A starting point might be to look at $n=4$, for which the middle circles are now constrained in some way (need to allow an exact incircle and circumcircle). The number of constraints appears to be $n-1$. It might be interesting to study the allowed $(r_-,r_+)$ for a given $n$.
Oct 13, 2013 at 16:34 comment added Gil Kalai Great question!
Oct 10, 2013 at 22:19 comment added Gerry Myerson I haven't looked at the paper, but the review of Paul Yiu, Rational Steiner porism, Forum Geom. 11 (2011) 237–249, MR2877262 suggests there might be something of interest there.
S Oct 10, 2013 at 21:48 history bounty started James Propp
S Oct 10, 2013 at 21:48 history notice added James Propp Draw attention
Oct 4, 2013 at 3:19 comment added James Propp Presumably the answer would be of the form $P_n(r_1,\dots,r_n,r_-,r_+)=0$ where $P_n$ is a homogeneous polynomial that is cyclically symmetric (mod $n$) in $r_1,\dots,r_n$. Perhaps an algebraic geometry argument tells us ahead of time that such a polynomial must exist? To get a sense of how big the degree of $P_n$ might need to be, one could look at the situation where $r_1=r_2=\dots=r_n=1$; then $r_- = (\csc \pi/n) - 1$ and $r_+ = (\csc \pi/n) + 1$ (or something like that). Does this give information about the degree of $P_n$?
Oct 3, 2013 at 18:37 history edited Ricardo Andrade
replaced tags
Oct 3, 2013 at 16:03 history edited Joseph O'Rourke CC BY-SA 3.0
Added image.
Oct 3, 2013 at 15:58 history asked James Propp CC BY-SA 3.0