Timeline for How to examine the convexity of a complex function numerically?
Current License: CC BY-SA 3.0
7 events
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Oct 19, 2013 at 15:57 | vote | accept | behrad mahboobi | ||
May 23, 2016 at 3:19 | |||||
Oct 6, 2013 at 6:43 | comment | added | Robert Israel | But you will have a hard time trying to prove its convexity numerically. | |
Oct 5, 2013 at 6:37 | comment | added | behrad mahboobi | strongly or strictly convexity always results in convexity. | |
Oct 4, 2013 at 17:09 | history | edited | Robert Israel | CC BY-SA 3.0 |
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Oct 4, 2013 at 15:28 | comment | added | Robert Israel | Actually strictly convex is not enough, you need the second derivative bounded away from $0$. | |
Oct 4, 2013 at 12:31 | comment | added | behrad mahboobi | you have assumed that the function is strictly convex at the first like of your post!! if it is strictly convex then it is convex too so why do we need third derivative in class $C^3$! | |
Oct 3, 2013 at 6:12 | history | answered | Robert Israel | CC BY-SA 3.0 |