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Oct 19, 2013 at 15:57 vote accept behrad mahboobi
May 23, 2016 at 3:19
Oct 6, 2013 at 6:43 comment added Robert Israel But you will have a hard time trying to prove its convexity numerically.
Oct 5, 2013 at 6:37 comment added behrad mahboobi strongly or strictly convexity always results in convexity.
Oct 4, 2013 at 17:09 history edited Robert Israel CC BY-SA 3.0
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Oct 4, 2013 at 15:28 comment added Robert Israel Actually strictly convex is not enough, you need the second derivative bounded away from $0$.
Oct 4, 2013 at 12:31 comment added behrad mahboobi you have assumed that the function is strictly convex at the first like of your post!! if it is strictly convex then it is convex too so why do we need third derivative in class $C^3$!
Oct 3, 2013 at 6:12 history answered Robert Israel CC BY-SA 3.0