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Oct 11, 2013 at 2:09 comment added Suvrit one minor point worth noting is that if $[\alpha_i^{j-1}\beta_j^{i-1}]$ is rank-1, (I'm running indices from $1,2,\ldots$), then $M=\text{diag}(\alpha)Z\text{diag}(\beta)$, which is clearly nonsingular. This begs the question: what is the largest rank that the matrix formed from the $\alpha$s and $\beta$s can have?
Oct 10, 2013 at 19:22 comment added Peter Mueller Checking all possibilities for $\alpha$ and $\beta$, the answer is affirmative for all $\ell\le12$.
Oct 10, 2013 at 18:09 comment added Suvrit @Peter: I used $\alpha$ a random $\pm 1$ vector, and $\beta=[-1,1,-1,\ldots,]$. But I think I'm just running into round-off---
Oct 9, 2013 at 14:51 comment added Binzhou Xia @PeterMueller: Yes. It seems that the fewer prime factors $l$ has, the easier the situation would be. So I think one may start the question when $l=p$ is prime (the $2p$th cyclotomic polynomial is also clear).
Oct 9, 2013 at 14:23 comment added Peter Mueller This question has the flavor of a theorem of Chebotarev on the non-singularity of the minors of the matrix with entry $\zeta^{ij}$ in position $(i,j)$, where $\zeta$ is a primitive $p$-th root of unity for a prime $p$.
Oct 9, 2013 at 14:20 comment added Peter Mueller @suv...rit: Which kind of reformulation did you use? For $l=40$, there are $2^{80}$ possibilities for the vectors $\alpha$ and $\beta$ ...
Oct 9, 2013 at 14:08 comment added Suvrit for me think broke at $l=40$, but should also break earlier---but I still suspect that this might be due to numerical roundoff (i.e., numerical rank was $l-1$)
Oct 9, 2013 at 8:03 comment added Binzhou Xia @suv....rit :Thanks! In your experiments, what is the smallest value of $l$ such that the matrix seems to be singular?
Oct 8, 2013 at 18:53 comment added Suvrit My experiments suggest that this matrix can be singular---however, due to numerical concerns, am not yet conclusively claiming singularity.
Oct 3, 2013 at 5:42 history edited Binzhou Xia CC BY-SA 3.0
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Oct 2, 2013 at 16:40 history edited Binzhou Xia
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Oct 2, 2013 at 16:31 history edited Binzhou Xia CC BY-SA 3.0
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Oct 2, 2013 at 7:49 history asked Binzhou Xia CC BY-SA 3.0