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Oct 1, 2013 at 15:46 vote accept Vassilis Parassidis
Oct 1, 2013 at 5:35 answer added Robert Israel timeline score: 2
Oct 1, 2013 at 5:19 review Close votes
Oct 1, 2013 at 20:47
Oct 1, 2013 at 4:45 comment added Vassilis Parassidis @AaronMeyerowitz.The first product converges to 2/pi. This product is well known, the Vieta product. The second product converges to the square root of e.
Oct 1, 2013 at 4:32 comment added Aaron Meyerowitz If you pick $x_0$ and then iterate $x_{n+1}=\sqrt\frac{1+x_n}{2}$ then the limit, if any, should be a number $L$ such that $L=\sqrt\frac{1+L}{2}.$ Solve that for $L$, find that neither solution is transcendental and observe that the limit does exist.
Oct 1, 2013 at 4:24 history edited Aaron Meyerowitz CC BY-SA 3.0
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Oct 1, 2013 at 4:14 history asked Vassilis Parassidis CC BY-SA 3.0