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Feb 6, 2010 at 16:00 answer added Ben Webster timeline score: 2
Feb 6, 2010 at 15:14 history edited Jean Delinez CC BY-SA 2.5
edited title
Feb 6, 2010 at 15:06 history edited Jean Delinez CC BY-SA 2.5
added 442 characters in body; added 3 characters in body
Feb 6, 2010 at 13:49 answer added Pavel Etingof timeline score: 5
Feb 6, 2010 at 12:24 history edited Ilya Nikokoshev CC BY-SA 2.5
title fix + retag
Feb 6, 2010 at 10:12 comment added José Figueroa-O'Farrill I am not sure I understand this question. What in the principal fibration is supposed to be the complex projective variety? The base? The total space? In the examples you have provided, it seems that it is the base of the fibration. If so, then just simply take your favourite variety and stick a principal bundle on it. Clearly this is too trivial an answer, so more likely than not I'm misunderstanding the question.
Feb 6, 2010 at 8:38 comment added Jean Delinez But isn't every homogeneous space automatically a principal bundle? As far as I can see, for any homogeneous $G$-space $X$, with stabilizer subgroup $H$ of some point $x \in X$, we have $X = G/H$. The projection $\pi:G \to G/H$, gives $G$ a fibred structure and the action of $H$ on the fibres is free and transitive, making $\pi:G \to X$ a principal $H$-bundle. Yes, all the examples I mentioned are homogeneous spaces, but I would be interested in examples that only principal bundles.
Feb 6, 2010 at 6:32 comment added Anton Geraschenko It looks like you mean "homogeneous space" (space with a transitive group action) rather than "principal bundle" (morphism with a free transitive group action on fibers).
Feb 6, 2010 at 6:18 history asked Jean Delinez CC BY-SA 2.5