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Feb 6, 2010 at 10:54 comment added darij grinberg Oh, it's actually online: gdz.sub.uni-goettingen.de/dms/load/toc/?PPN=PPN243919689_0341
Feb 6, 2010 at 10:49 vote accept darij grinberg
Feb 6, 2010 at 10:49 comment added darij grinberg Okay, I now found the first page of the reference: reference-global.com/doi/abs/10.1515/crll.1983.341.87 and indeed it claims that the Burnside ring is just pre-$\lambda$ rather than $\lambda$. And a reference to Siebeneicher claiming that it is $\lambda$ if $G$ is cyclic (which should be Witt vector theory again). My question is settled.
Feb 6, 2010 at 9:39 comment added darij grinberg Thanks a lot. This kills the conjecture at least. I assume that for cyclic $K$, it is not particularly hard (one can wlog assume that $G=K$, and $B\left(G\right)$ for cyclic $G$ should be some kind of stunted Witt rings).
Feb 6, 2010 at 2:39 history answered Charles Rezk CC BY-SA 2.5