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Sep 29, 2013 at 2:00 vote accept user40096
Sep 28, 2013 at 20:04 answer added David Eppstein timeline score: 4
Sep 28, 2013 at 17:00 comment added Seva @user40096: I overlooked the difference between $N$ and $N-1$. My earlier comments removed.
Sep 28, 2013 at 14:42 comment added Flo Pfender one counter example for $N=2$ would be an odd cycle. For $N\ge 3$, I am not quite sure.
Sep 28, 2013 at 13:58 comment added user40096 You did not see my question carefully!The maximal degree of $G$ is $N$,but for any $N$-order complete subgraph $H$ of $G$,the degree of every vertex of $H$ is $N$-1.
Sep 28, 2013 at 10:29 comment added user40096 First,if $I$ is empty,$I$ does not satisfes "for every $N$ -order complete subgraph $H$ of $G$, the intersection of $I$ and $V$($H$) is not empty"!Second,as you said,if the intersection of $I$ and $V$($H$) is empty,how do you know the vertex in $I$ is not adjacent to any vertex of $H$?
S Sep 28, 2013 at 7:25 history suggested Thomas Kahle CC BY-SA 3.0
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Sep 28, 2013 at 7:15 review Suggested edits
S Sep 28, 2013 at 7:25
Sep 28, 2013 at 6:24 history asked user40096 CC BY-SA 3.0