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Sep 27, 2013 at 17:14 history edited Vidit Nanda CC BY-SA 3.0
fixed 1 + ... + k = k(k+1)/2
Sep 27, 2013 at 17:07 history edited Vidit Nanda CC BY-SA 3.0
Asymptotics on the product...
Sep 27, 2013 at 16:53 comment added user2529 Thank you Vidit. Your computation gives a lower bound for $n_0(\epsilon)$. But this lower bound may not be sharp asymptotically in $\epsilon$.
Sep 27, 2013 at 16:15 history answered Vidit Nanda CC BY-SA 3.0