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Sep 26, 2013 at 12:48 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 26, 2013 at 12:23 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 26, 2013 at 12:07 comment added Francesco Polizzi If $V$ is irreducible of degree $d$, in general the abelianization of $\pi_1(U)$ is $\mathbb{Z}/d \mathbb{Z}$. However, if $V$ is not normal crossing in codimension $1$, it may happen that $\pi_1(U)$ is not abelian. I added a couple of classical examples illustating this situation.
Sep 25, 2013 at 14:43 comment added user19475 Perhaps by considering $\mathrm{Pic}(U) = \mathrm{Cl}(U)$ and $H^1(U,\mathbf{Z}(1))$.
Sep 25, 2013 at 14:40 comment added user19475 Is there a connection between of $\mathrm{Cl}(U) = \mathbf{Z}/d$ and $\pi_1(U)$ as for $U = \mathbf{P}^n \setminus V$ in general?
Sep 25, 2013 at 12:38 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 25, 2013 at 12:20 vote accept IMeasy
Sep 25, 2013 at 12:19 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 25, 2013 at 10:17 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 25, 2013 at 9:52 history answered Francesco Polizzi CC BY-SA 3.0