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Sep 26, 2013 at 6:25 comment added Samuel Monnier Are you asking why the intersection form is even on $H^2(X,\mathbb{Z})$ when $X$ is a spin 4-manifold? This follows from the fact that the degree 2 Wu class, given in terms of the Stiefel-Whitney classes by $w_2 + w_1^2$, vanishes for spin manifolds.
Sep 25, 2013 at 18:58 history edited Ryan Thorngren CC BY-SA 3.0
I've rewritten the question somewhat
Sep 25, 2013 at 5:13 comment added Chris Gerig A post of mine from a while ago is related: mathoverflow.net/questions/100746/…
Sep 25, 2013 at 0:41 comment added Chris Gerig Well first, CS is not a characteristic class, because $X$ has boundary (the Chern class arises from closed $X$). And I can choose my $X$ to be simply-connected, because the corresponding cobordism group is trivial.
Sep 25, 2013 at 0:21 comment added Ryan Thorngren I don't think I'm really switching gears. The Chern-Simons invariant is a sort of characteristic class of the $U(1)$ gauge bundle. Perhaps I should have chosen a more simple motivating example. By the way, does this definition of the Chern-Simons invariant only work for simply connected manifolds?
Sep 24, 2013 at 21:40 answer added johndoe timeline score: 2
Sep 24, 2013 at 21:28 comment added Chris Gerig I'm having trouble following this. For your question, what are you referring to by "what the spin structure gives you"? In relation to the motivation, the spin structure gives $w_2(M)=0$ which on a simply-connected 4-manifold is equivalent to having an even intersection form. I don't see why you switch gears to "characteristic classes of bundles other than the tangent bundle".
Sep 24, 2013 at 20:00 history asked Ryan Thorngren CC BY-SA 3.0