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Sep 24, 2013 at 12:13 history edited Francesco Polizzi CC BY-SA 3.0
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Sep 24, 2013 at 12:00 comment added Francesco Polizzi Of course. I should have said "in order to compute the Chern classes and the determinant of the symmetric powers of $E$", or just "in order to compute the determinant of the symmetric powers of $E$", since actually we are not interested in Chern classes.
Sep 24, 2013 at 11:07 comment added swalker But, we know that line bundle is not determined by its Chern class. (unless on $\mathbb{P}^n$, you know for example)
Sep 24, 2013 at 9:53 history answered Francesco Polizzi CC BY-SA 3.0