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Sep 24, 2013 at 7:48 comment added user23860 @YvesCornulier: I think the continuity of co-amenability is an immediate corollary of the fixed point property. So ignore my previous comment. BTW, I appreciate your help.
Sep 24, 2013 at 7:14 comment added YCor The answer is negative: indeed otherwise by considering the dense homomorphism into $PGL_2(\mathbb{Q}_p)$, we would infer that $PGL_2(\mathbb{Z}_p)$ is co-amenable in the latter. Since it is compact, this would mean that $PGL_2(\mathbb{Q}_p)$ is amenable, a contradiction.
Sep 24, 2013 at 7:12 comment added YCor This is usually called "$H$ is co-amenable in $G$".
Sep 24, 2013 at 4:40 history asked user23860 CC BY-SA 3.0