Timeline for Strange (or stupid) arithmetic derivation
Current License: CC BY-SA 3.0
2 events
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| Sep 21, 2013 at 22:52 | comment | added | Lucia | I don't understand this answer either! If $k_0=p^{k_1}$ then except for some trivial cases, it cannot be that $k_0+k_1-1$ is a power of $p$. So I don't understand what ``proceeding in this fashion" means. | |
| Sep 21, 2013 at 18:27 | history | answered | Vidit Nanda | CC BY-SA 3.0 |