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Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces such that:

$X_{n}$ is a regular$^1$ CW-complex of constant local dimension$^3$ $n$, it is of finite type$^4$, boundaryless$^2$, unbounded, uniform$^5$, and it is the $n$-skeleton of $X_{n+1}$, which is n-connected. Moreover, the distances $d_{n}$ , $d_{n+1}$ generate the same topology on $X_{n}$ and $\forall x,y \in X_{n} \ d_{n+1}(x,y) \le d_{n}(x,y)$.
Finally $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, through the inclusion map $X_{n} \subset X_{n+1}$, and a distance $d$ on $ \bigcup{X_{n}}$ is defined (for $x, y \in X_{n_0}$) by $d(x,y) := lim_{n (\ge n_0) \to \infty} d_{n}(x,y)$.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.
Question : Is $X$ weakly contractible ?

Remark: Some of these conditions could be useless for a proof, and others, highly generalized.
Motivation: See herehere for applications to geometric group theory and noncommutative geometry.


$^1$Regular (for a CW complex) : the attaching maps are homeomorphism (see this postthis post).
$^2$Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.
$^3$Constant local dimension : the topological dimension of all neighborhood of all point, is constant.
$^4$Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.
$^5$Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces such that:

$X_{n}$ is a regular$^1$ CW-complex of constant local dimension$^3$ $n$, it is of finite type$^4$, boundaryless$^2$, unbounded, uniform$^5$, and it is the $n$-skeleton of $X_{n+1}$, which is n-connected. Moreover, the distances $d_{n}$ , $d_{n+1}$ generate the same topology on $X_{n}$ and $\forall x,y \in X_{n} \ d_{n+1}(x,y) \le d_{n}(x,y)$.
Finally $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, through the inclusion map $X_{n} \subset X_{n+1}$, and a distance $d$ on $ \bigcup{X_{n}}$ is defined (for $x, y \in X_{n_0}$) by $d(x,y) := lim_{n (\ge n_0) \to \infty} d_{n}(x,y)$.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.
Question : Is $X$ weakly contractible ?

Remark: Some of these conditions could be useless for a proof, and others, highly generalized.
Motivation: See here for applications to geometric group theory and noncommutative geometry.


$^1$Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).
$^2$Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.
$^3$Constant local dimension : the topological dimension of all neighborhood of all point, is constant.
$^4$Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.
$^5$Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces such that:

$X_{n}$ is a regular$^1$ CW-complex of constant local dimension$^3$ $n$, it is of finite type$^4$, boundaryless$^2$, unbounded, uniform$^5$, and it is the $n$-skeleton of $X_{n+1}$, which is n-connected. Moreover, the distances $d_{n}$ , $d_{n+1}$ generate the same topology on $X_{n}$ and $\forall x,y \in X_{n} \ d_{n+1}(x,y) \le d_{n}(x,y)$.
Finally $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, through the inclusion map $X_{n} \subset X_{n+1}$, and a distance $d$ on $ \bigcup{X_{n}}$ is defined (for $x, y \in X_{n_0}$) by $d(x,y) := lim_{n (\ge n_0) \to \infty} d_{n}(x,y)$.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.
Question : Is $X$ weakly contractible ?

Remark: Some of these conditions could be useless for a proof, and others, highly generalized.
Motivation: See here for applications to geometric group theory and noncommutative geometry.


$^1$Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).
$^2$Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.
$^3$Constant local dimension : the topological dimension of all neighborhood of all point, is constant.
$^4$Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.
$^5$Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Great relooking!!!
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Sebastien Palcoux
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Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces verifying such that:

  • $X_{n}$ is a regular CW complex of constant local dimension $n$.
  • $X_{n}$ is of finite type, boundaryless, unbounded and uniform.
  • $X_{n+1}$ is n-connected.
  • $X_{n}$ is the $n$-skeleton of $X_{n+1}$
  • The distance $d_{n}$ and $d_{n+1}$ generate the same topology on $X_{n}$.
  • $\forall x,y \in X_{n}$ : $d_{n+1}(x,y) \le d_{n}(x,y)$.
  • $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, established by the inclusion map $X_{n} \subset X_{n+1}$.
  • Let $d$ on $ \bigcup{X_{n}}$ defined by $d(x,y) = lim_{n \to \infty} d_{n}(x,y)$, then $d$ is a distance.

Remark : There$X_{n}$ is a small abuse inregular$^1$ CW-complex of constant local dimension$^3$ $n$, it is of finite type$^4$, boundaryless$^2$, unbounded, uniform$^5$, and it is the previous definition because $d_{n}(x,y)$$n$-skeleton of $X_{n+1}$, which is defined only for $x, y \in X_{n}$n-connected. But because we takeMoreover, the distances $d_{n}$ $n \to \infty$, there$d_{n+1}$ generate the same topology on $X_{n}$ and $\forall x,y \in X_{n} \ d_{n+1}(x,y) \le d_{n}(x,y)$.
Finally $(X_{n},d_{n})$ is no problemquasi-isometric to $(X_{n+1},d_{n+1})$, through the inclusion map $X_{n} \subset X_{n+1}$, and a distance $d$ on $ \bigcup{X_{n}}$ is defined (for $x, y \in X_{n_0}$) by $d(x,y) := lim_{n (\ge n_0) \to \infty} d_{n}(x,y)$.

DefinitionDefinition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.
Question : Is $X$ weakly contractible ?

Problem : Is $X$ weakly contractible ?

Remark :Remark: Some of these conditions could be useless for a proof, and others, highly generalized.
Motivation: See here for applications to geometric group theory and noncommutative geometry.


Some definitions :

Regular$^1$Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).

Boundaryless
$^2$Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.

Constant local dimension
$^3$Constant local dimension : the topological dimension of all neighborhood of all point, is constant.

Finite type
$^4$Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.

Uniform
$^5$Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces verifying :

  • $X_{n}$ is a regular CW complex of constant local dimension $n$.
  • $X_{n}$ is of finite type, boundaryless, unbounded and uniform.
  • $X_{n+1}$ is n-connected.
  • $X_{n}$ is the $n$-skeleton of $X_{n+1}$
  • The distance $d_{n}$ and $d_{n+1}$ generate the same topology on $X_{n}$.
  • $\forall x,y \in X_{n}$ : $d_{n+1}(x,y) \le d_{n}(x,y)$.
  • $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, established by the inclusion map $X_{n} \subset X_{n+1}$.
  • Let $d$ on $ \bigcup{X_{n}}$ defined by $d(x,y) = lim_{n \to \infty} d_{n}(x,y)$, then $d$ is a distance.

Remark : There is a small abuse in the previous definition because $d_{n}(x,y)$ is defined only for $x, y \in X_{n}$. But because we take $n \to \infty$, there is no problem.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.

Problem : Is $X$ weakly contractible ?

Remark : Some of these conditions could be useless for a proof, and others, highly generalized.


Some definitions :

Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).

Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.

Constant local dimension : the topological dimension of all neighborhood of all point, is constant.

Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.

Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces such that:

$X_{n}$ is a regular$^1$ CW-complex of constant local dimension$^3$ $n$, it is of finite type$^4$, boundaryless$^2$, unbounded, uniform$^5$, and it is the $n$-skeleton of $X_{n+1}$, which is n-connected. Moreover, the distances $d_{n}$ , $d_{n+1}$ generate the same topology on $X_{n}$ and $\forall x,y \in X_{n} \ d_{n+1}(x,y) \le d_{n}(x,y)$.
Finally $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, through the inclusion map $X_{n} \subset X_{n+1}$, and a distance $d$ on $ \bigcup{X_{n}}$ is defined (for $x, y \in X_{n_0}$) by $d(x,y) := lim_{n (\ge n_0) \to \infty} d_{n}(x,y)$.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.
Question : Is $X$ weakly contractible ?

Remark: Some of these conditions could be useless for a proof, and others, highly generalized.
Motivation: See here for applications to geometric group theory and noncommutative geometry.


$^1$Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).
$^2$Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.
$^3$Constant local dimension : the topological dimension of all neighborhood of all point, is constant.
$^4$Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.
$^5$Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Notice removed Draw attention by Sebastien Palcoux
Bounty Ended with Sergei Ivanov's answer chosen by Sebastien Palcoux
I have removed the optional question, because I have posted another question with this additional assumption.
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Sebastien Palcoux
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Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces verifying :

  • $X_{n}$ is a regular CW complex of constant local dimension $n$.
  • $X_{n}$ is of finite type, boundaryless, unbounded and uniform.
  • $X_{n+1}$ is n-connected.
  • $X_{n}$ is the $n$-skeleton of $X_{n+1}$
  • The distance $d_{n}$ and $d_{n+1}$ generate the same topology on $X_{n}$.
  • $\forall x,y \in X_{n}$ : $d_{n+1}(x,y) \le d_{n}(x,y)$.
  • $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, established by the inclusion map $X_{n} \subset X_{n+1}$.
  • Let $d$ on $ \bigcup{X_{n}}$ defined by $d(x,y) = lim_{n \to \infty} d_{n}(x,y)$, then $d$ is a distance.

Remark : There is a small abuse in the previous definition because $d_{n}(x,y)$ is defined only for $x, y \in X_{n}$. But because we take $n \to \infty$, there is no problem.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.

Problem : Is $X$ weakly contractible ?

Remark : Some of these conditions could be useless for a proof, and others, highly generalized.

Optional problem : By inspiring with the (accepted) answer of Sergei Ivanov, I ask here the same question with the following additional assumption :
Rigidity assumption : Let $S$ be a connected subspace of $X_{n}$ such that $S$ contains the geodesic paths between all its points, for $d_{n}$ and $d_{n+1}$, then $d_{n} = d_{n+1}$ on $S$.


Some definitions :

Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).

Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.

Constant local dimension : the topological dimension of all neighborhood of all point, is constant.

Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.

Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces verifying :

  • $X_{n}$ is a regular CW complex of constant local dimension $n$.
  • $X_{n}$ is of finite type, boundaryless, unbounded and uniform.
  • $X_{n+1}$ is n-connected.
  • $X_{n}$ is the $n$-skeleton of $X_{n+1}$
  • The distance $d_{n}$ and $d_{n+1}$ generate the same topology on $X_{n}$.
  • $\forall x,y \in X_{n}$ : $d_{n+1}(x,y) \le d_{n}(x,y)$.
  • $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, established by the inclusion map $X_{n} \subset X_{n+1}$.
  • Let $d$ on $ \bigcup{X_{n}}$ defined by $d(x,y) = lim_{n \to \infty} d_{n}(x,y)$, then $d$ is a distance.

Remark : There is a small abuse in the previous definition because $d_{n}(x,y)$ is defined only for $x, y \in X_{n}$. But because we take $n \to \infty$, there is no problem.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.

Problem : Is $X$ weakly contractible ?

Remark : Some of these conditions could be useless for a proof, and others, highly generalized.

Optional problem : By inspiring with the (accepted) answer of Sergei Ivanov, I ask here the same question with the following additional assumption :
Rigidity assumption : Let $S$ be a connected subspace of $X_{n}$ such that $S$ contains the geodesic paths between all its points, for $d_{n}$ and $d_{n+1}$, then $d_{n} = d_{n+1}$ on $S$.


Some definitions :

Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).

Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.

Constant local dimension : the topological dimension of all neighborhood of all point, is constant.

Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.

Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

Let $(X_{n},d_{n})_{n \in \mathbb{N}}$ be a sequence of complete geodesic metric spaces verifying :

  • $X_{n}$ is a regular CW complex of constant local dimension $n$.
  • $X_{n}$ is of finite type, boundaryless, unbounded and uniform.
  • $X_{n+1}$ is n-connected.
  • $X_{n}$ is the $n$-skeleton of $X_{n+1}$
  • The distance $d_{n}$ and $d_{n+1}$ generate the same topology on $X_{n}$.
  • $\forall x,y \in X_{n}$ : $d_{n+1}(x,y) \le d_{n}(x,y)$.
  • $(X_{n},d_{n})$ is quasi-isometric to $(X_{n+1},d_{n+1})$, established by the inclusion map $X_{n} \subset X_{n+1}$.
  • Let $d$ on $ \bigcup{X_{n}}$ defined by $d(x,y) = lim_{n \to \infty} d_{n}(x,y)$, then $d$ is a distance.

Remark : There is a small abuse in the previous definition because $d_{n}(x,y)$ is defined only for $x, y \in X_{n}$. But because we take $n \to \infty$, there is no problem.

Definition : Let $X:=\overline{\bigcup{X_{n}}}$ be the completion of the metric space $\bigcup{X_{n}}$ with $d$.

Problem : Is $X$ weakly contractible ?

Remark : Some of these conditions could be useless for a proof, and others, highly generalized.


Some definitions :

Regular (for a CW complex) : the attaching maps are homeomorphism (see this post).

Boundaryless (for a regular CW complex) : the boundary of each closed cell is contained is the union of the boundaries of other closed cells.

Constant local dimension : the topological dimension of all neighborhood of all point, is constant.

Finite type : finitely many $r$-cells ending in a fixed $(r-1)$-cell.

Uniform : For all $r$-cell $c_{1}$ and $c_{2}$, there is a neighborhood $n_{1}$ of $c_{1}$ and $n_{2}$ of $c_{1}$, such that $n_{1}$ is homeomorphic to $n_{2}$.

I clarify about the assumption that d is a distance. I add an optional problem (inspired with the accepted answer of Sergei).
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Sebastien Palcoux
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Notice added Draw attention by Sebastien Palcoux
Bounty Started worth 50 reputation by Sebastien Palcoux
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Sebastien Palcoux
  • 27k
  • 5
  • 74
  • 186
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