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Sep 23, 2022 at 18:58 comment added The Amplitwist The link to Borchmann's diploma thesis in a comment above is broken, but it can be found now at iccl.inf.tu-dresden.de/w/images/8/81/Orbifolds.pdf.
Oct 1, 2013 at 17:39 answer added David Eppstein timeline score: 2
Oct 1, 2013 at 16:46 answer added Andrew D. King timeline score: 4
Sep 19, 2013 at 8:51 comment added Martin Rubey This is also a special case of the "generalized lexicographic product of graphs", also known as "local join" or "composition" $G[H_1,H_2,\dots,H_n]$ where the $H_i$ consist of isolated vertices only. See eg. Sabidussi, "Graph derivatives" or item 16 of Section 2.7 in Cvetkovic, Doob, Sachs, "Spectra of Graphs".
Sep 19, 2013 at 8:49 vote accept Aline Parreau
Sep 19, 2013 at 8:49 vote accept Aline Parreau
Sep 19, 2013 at 8:49
Sep 19, 2013 at 8:49 vote accept Aline Parreau
Sep 19, 2013 at 8:49
Sep 19, 2013 at 2:14 answer added Timothy Chow timeline score: 2
Sep 18, 2013 at 22:45 answer added Flo Pfender timeline score: 8
Sep 18, 2013 at 22:22 comment added Tobias Schlemmer A similar construction has been called binary relation orbifold (Borchmann, Daniel: Context Orbifolds, Diploma Thesis, TU Dresden, 2009, link).
Sep 18, 2013 at 13:23 answer added Ira Gessel timeline score: 0
Sep 18, 2013 at 10:16 answer added Felix Goldberg timeline score: 1
Sep 18, 2013 at 9:49 comment added HJRW It's heavily used in subsequent work on outer automorphisms of graph groups. Look at the citations of Servatius' paper. The reference is: H. Servatius, Automorphisms of graph groups, J. Algebra 126 (1989), no. 1, 34–60.
Sep 18, 2013 at 9:32 answer added Tony Huynh timeline score: 0
Sep 18, 2013 at 9:16 comment added Aline Parreau Indeed, the equivalence classes with this relation will be either clique or stable sets. Do you know if anyone else use this relation and the reduced graph behind ?
Sep 18, 2013 at 8:57 comment added HJRW A similar but not identical equivalence relation was defined by Servatius in his study of graph groups (aka right-angled Artin groups). Write $u\geq v$ if $N(v)\subseteq N(u)\cup\{u\}$ and $u\sim v$ if $u\geq v$ and $v\geq u$. In other words, $u$ and $v$ are also allowed to be adjacent.
Sep 18, 2013 at 8:50 review First posts
Sep 18, 2013 at 8:57
Sep 18, 2013 at 8:33 history asked Aline Parreau CC BY-SA 3.0