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Timeline for Pseudoinverse of Neumann-Laplacian

Current License: CC BY-SA 3.0

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Sep 17, 2013 at 12:43 history edited Guido Kanschat CC BY-SA 3.0
remove question about pseudo inverse
Sep 17, 2013 at 12:43 comment added Guido Kanschat Then $A^\dagger$ is continuous iff the range of $A$ is closed
Sep 17, 2013 at 12:36 comment added Elias Ka Definition of Pseudo-Inverse: Let $$A\colon X\to Y $$ be a bounded linear operator between two hilbert-spaces. Further define $$\widetilde{A}\colon \mathrm{ker}(A)^\perp \to \mathrm{ran}(A)$$. Then we define $$A^\dagger\colon \mathrm{ran}(A)\otimes \mathrm{ran}(A)^\perp \subset Y \to X \\ y \mapsto \widetilde{A}^{-1} P_{\mathrm{ran}(A)} y$$ Here $P_{\mathrm{ran}(A)}$ is the projector onto (the closure of) the range of $A$.
Sep 17, 2013 at 12:25 history answered Guido Kanschat CC BY-SA 3.0