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Timeline for Barr's theorem and constructivity?

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Sep 26, 2013 at 17:58 comment added Andreas Blass Consider a nondegenerate but non-Boolean Grothendieck topos $E$. Diaconescu's proof that AC implies excluded middle can be used to show that an internal version of choice fails in $E$. (More precisely, one can give an object $A$ such that the internal sentence "for every equivalence relation on $A$, the map from $A$ to the quotient has a section" is false.) So in $E$, from any set (even the empty set) of geometric hypotheses plus AC one can deduce anything, even the geometric conclusion "false", because AC fails. That inference won't work constructively.
Sep 26, 2013 at 16:28 comment added Zhen Lin @SimonHenry That is a very different question than your original question! But the "logical form of Barr's theorem" is not obviously true in the internal logic of even a Grothendieck topos – for one thing, a topos that is "internally localic" may not actually be localic.
Sep 26, 2013 at 14:45 comment added Simon Henry Yes that's what I mean. What I call the logical form of Barr's theorem is "If from a family of geometric hypothesis I can deduce a geometric conclusion using the axiom of choice then I can deduce it also constructively". This theorem hold internally in any Grothendeick topos. But one generally said that it is non-constructive, I want a proof of this non-constructivity by a counterexample in a topos (which has to be elementary.)
Sep 26, 2013 at 14:08 comment added Andreas Blass Does the edit mean that you want to allow $H$ and $C$ to be in a language internal to an elementary topos $E$, and that the infinitary disjunctions of geometric logic can be indexed by objects of $E$, and that the "set" $H$ itself might not be a "real" set but an object of $E$, and that deducibility is to be interpreted internally in $E$? Or only some of these? "Deducible using the axiom of choice" looks suspicous in $E$ if $E$ doesn't satisfy the (internal) AC. Did you perhaps want the deducibility to work also in all topoi defined over $E$?
Sep 26, 2013 at 13:57 comment added Zhen Lin You've misunderstood: the completeness theorem I'm referring to is the one that says that any coherent sequent in a coherent theory that is true in all Grothendieck toposes can also be proved using the rules of inference of coherent logic. In particular it is valid in elementary toposes.
Sep 26, 2013 at 12:56 history edited Simon Henry CC BY-SA 3.0
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Sep 15, 2013 at 16:18 answer added Zhen Lin timeline score: 6
Sep 15, 2013 at 14:18 history asked Simon Henry CC BY-SA 3.0