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when toggle format what by license comment
Jun 15, 2010 at 1:41 history edited Gerry Myerson CC BY-SA 2.5
improved formatting
Feb 6, 2010 at 15:30 comment added Reid Barton Using $\mathbb{Z}(\mathbb{R}/\mathbb{Z})$ doesn't seem any better; now you're just counting rectangles by their dimensions mod 1, and the fact that they tile a larger rectangle has no counterpart in algebra.
Feb 5, 2010 at 8:27 history edited Richard Eager CC BY-SA 2.5
added 167 characters in body
Feb 5, 2010 at 4:06 comment added Reid Barton Isn't, say, $\pi \otimes \frac12 = \frac\pi2 \otimes 1 = 0$ in $\mathbb{R}/\mathbb{Z} \otimes \mathbb{R}/\mathbb{Z}$? So we can only conclude that the original rectangle has a rational side?
Feb 5, 2010 at 2:24 history answered Richard Eager CC BY-SA 2.5