Skip to main content
5 events
when toggle format what by license comment
Sep 14, 2013 at 17:55 history edited Joel David Hamkins CC BY-SA 3.0
added 724 characters in body
Sep 14, 2013 at 14:06 comment added Joel David Hamkins @Silvi, the same argument works even if you don't have the final point, since every continuous function $\kappa\to\mathbb{R}$ is eventually constant, because $\kappa$ has uncountable cofinality. So we would also have $|C(Y)|=\kappa$. But in this case, $Y$ would not be compact, although still Tychonoff.
Sep 14, 2013 at 13:52 comment added user37834 +1 Nice. If $Y = \kappa$ ($\kappa$ as above) then what is the cardinality of $C(Y)$? Is it $\kappa$ !?
Sep 14, 2013 at 12:41 vote accept CommunityBot
Sep 14, 2013 at 12:12 history answered Joel David Hamkins CC BY-SA 3.0