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Timeline for redundant relations

Current License: CC BY-SA 3.0

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Sep 13, 2013 at 11:23 comment added François G. Dorais Thanks @Stefan, that's what I thought. (And I just cleared my confusion, which was mostly due to lack of caffeine.)
Sep 13, 2013 at 9:14 comment added Stefan Kohl @FrançoisG.Dorais: A group is called 'linear' iff it embeds into ${\rm GL}(n,\mathbb{C})$ for some $n \in \mathbb{N}$.
Sep 13, 2013 at 4:05 comment added François G. Dorais @BenjaminSteinberg: I'm still confused by your comment but I can't tell why. What is the definition of a linear group?
Sep 13, 2013 at 1:24 comment added Benjamin Steinberg @JoelDavidHamkins, you cannot enumerate proofs when you restrict the class of groups you are looking at to linear (or finite) groups. We have left the varietal setting. There are consequences of relations that are true in all linear groups but not all groups. For example let <X|R> be a finite presentation of an infinite simple group. Then R implies x=1 in all linear groups for every x in X because no infinite fg simple group has a non-trivial finite dimensional rep. But of course x=1 is not a consequence of R in all groups so there is no equational proof.
Sep 13, 2013 at 1:19 comment added Joel David Hamkins @BenjaminSteinberg, I'm confused by your comment, since if implication checking is co-re, then it would have to be decidable, since clearly implication checking is also ce by enumerating proofs.
Sep 13, 2013 at 1:16 comment added Benjamin Steinberg @JoelDavidHamkins, the undecidability with respect to the implications of linear groups is a slightly different problem. Due to residual finiteness checking implications is co-re. I will say more in my answer.
Sep 13, 2013 at 0:01 comment added Joel David Hamkins Yes, I agree. I meant only to point out that indeed it is undecidable in the general case, since the comments expressed some degree of uncertainty about this.
Sep 12, 2013 at 23:55 comment added Martin Brandenburg This doesn't really address the question. The OP already noticed that the general case is hard/undecidable. But I think that the question deals with concrete cases.
Sep 12, 2013 at 23:51 history edited Joel David Hamkins CC BY-SA 3.0
added 18 characters in body
Sep 12, 2013 at 23:33 comment added Joel David Hamkins I'm not sure how your context of having matrices affects the situation.
Sep 12, 2013 at 23:32 history answered Joel David Hamkins CC BY-SA 3.0