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Michael Hardy
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Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$$\bigcap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \bigcup_{j\not = i} H_j$. Can $\bigcap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \bigcup_{j\not = i} H_j$. Can $\bigcap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\bigcap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \bigcup_{j\not = i} H_j$. Can $\bigcap_{j=1}^n \partial H_j$ be a single point?

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Michael Hardy
  • 1
  • 12
  • 85
  • 126

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \cup_{j\not = i} H_j$$x \not \in \bigcup_{j\not = i} H_j$. Can $\cap_{j=1}^n \partial H_j$$\bigcap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \cup_{j\not = i} H_j$. Can $\cap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \bigcup_{j\not = i} H_j$. Can $\bigcap_{j=1}^n \partial H_j$ be a single point?

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Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and $H_i \not = \cap_{j=1}^n H_j$ for alleach $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \cup_{j\not = i} H_j$. Can $\cap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and $H_i \not = \cap_{j=1}^n H_j$ for all $i=1,2,\dots,n$. Can $\cap_{j=1}^n \partial H_j$ be a single point?

Let $H_1,H_2,\dots,H_n$ be compact and convex sets in $\mathbb{R}^n$ such that $\cap_{j=1}^n H_j$ has non-empty interior and for each $i=1,2,\dots,n$ there exist at least one element $x \in H_i$ such that $x \not \in \cup_{j\not = i} H_j$. Can $\cap_{j=1}^n \partial H_j$ be a single point?

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