Timeline for Are these rings of functions isomorphic?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 13, 2013 at 19:21 | vote | accept | CommunityBot | ||
| Sep 13, 2013 at 17:37 | comment | added | Pietro Majer | I agree. Note that in both rings the constant $-1$ can be characterized multiplicatively as the only square root $r$ of $1$ such that for any nonzero square $q$ the element $rq$ is not a square. So the argument I wrote below actually shows that $R$ and $S$ have non-isomorphic multiplicative structures. | |
| Sep 13, 2013 at 16:57 | review | Close votes | |||
| Sep 13, 2013 at 19:05 | |||||
| Sep 13, 2013 at 15:09 | answer | added | Dag Oskar Madsen | timeline score: 8 | |
| Sep 13, 2013 at 13:45 | comment | added | Dag Oskar Madsen | @Sally Give me time, I'm writing down a proof. The key is looking at primitive idempotents. | |
| Sep 13, 2013 at 13:33 | comment | added | user30300 | @DagOskarMadsen I am not sure about that | |
| Sep 12, 2013 at 14:55 | comment | added | Dag Oskar Madsen | The sets of idempotents of $R$ and $S$ have non-isomorphic multiplicative structure. | |
| Sep 12, 2013 at 14:38 | answer | added | Pietro Majer | timeline score: 17 | |
| Sep 12, 2013 at 10:19 | review | First posts | |||
| Sep 12, 2013 at 10:50 | |||||
| Sep 12, 2013 at 10:04 | history | asked | user39207 | CC BY-SA 3.0 |