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Sep 12, 2013 at 11:01 history edited Horizonto CC BY-SA 3.0
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Sep 12, 2013 at 11:00 comment added Horizonto Thanks very much. The origin condition is that $f$ is a diffeomorphism to its image. I have improperly dropped this condition.
Sep 12, 2013 at 9:34 comment added Pietro Majer Of course you also need to assume that $f(B)=B$, as assuming just $f(B)\subset B$ allows non-injective locally invertible maps $f:B\to B$
Sep 11, 2013 at 12:05 history edited Horizonto CC BY-SA 3.0
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Sep 11, 2013 at 12:00 comment added Horizonto Thank you, I have corrected the description of the problem.
Sep 11, 2013 at 8:45 comment added Pietro Majer Are you sure? Here $df(x)$ may be singular already at some point of $B$. I think you had in mind an hypothesis on $\|df(x)^{-1}\|$ instead, like in Hadamard's theorem in fact.
Sep 11, 2013 at 6:21 history asked Horizonto CC BY-SA 3.0