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May 5, 2021 at 19:07 history edited John Pardon
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Sep 10, 2013 at 20:58 comment added Oldřich Spáčil Yes, I do understand you're interested in the Lag -> Leg direction... In my second comment I just tried to point out that the other direction seems easier to me, especially if in your setup you start with a Legendrian submanifold and only then consider symplectizations etc. Otherwise I can't come up with anything better than Alan Weinstein's remark on the $\mathbb{R}$-equivariancy.
Sep 10, 2013 at 20:10 comment added Chris Gerig Sorry, my question is focusing on the possibility to pass from Lagrangian neighborhood to Legendrian neighborhood (whereas the answers thus far are only showing me how to get a Legendrian neighborhood).
Sep 10, 2013 at 19:05 history edited Chris Gerig CC BY-SA 3.0
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Sep 10, 2013 at 17:23 comment added Oldřich Spáčil Also, my feeling is that you'd rather prove the Lagrangian nbhd theorem from the Legendrian one since you supposedly start with a contact manifold and its Legendrian and then consider the symplectization? If I'm not mistaken, the symplectization of $J^{1}K$ is symplectomorphic to $T^{*}(K\times \mathbb{R})$.
Sep 10, 2013 at 17:13 comment added Oldřich Spáčil You're right that Moser's method works well for proving a Legendrian nbhd theorem -- a tubular neighbourhood of $K$ is contactomorphic to a neighbourhood of the zero section of the 1-jet bundle $J^{1}K$ as described in the answers below. A proof can be found in Geiges's book An Introduction to contact topology, Theorem 2.5.8 and Example 2.5.11. You can even make the contactomorphism to be strict, i.e. preserving a given contact form -- a proof of this version is in Kriegl, Michor: The convenient setting of global analysis, Proposition 43.18 (this book is available from Michor's website).
Sep 10, 2013 at 9:24 answer added Andy McI timeline score: 1
Sep 10, 2013 at 6:55 answer added Giovanni Moreno timeline score: 1
Sep 10, 2013 at 0:03 history asked Chris Gerig CC BY-SA 3.0