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Sep 14, 2013 at 11:41 vote accept Niemi
Sep 14, 2013 at 11:41 vote accept Niemi
Sep 14, 2013 at 11:41
Sep 12, 2013 at 9:44 answer added Niemi timeline score: 4
Sep 12, 2013 at 9:41 history edited Niemi CC BY-SA 3.0
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Sep 9, 2013 at 8:48 history edited Niemi CC BY-SA 3.0
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Sep 6, 2013 at 19:28 comment added Benjamin Steinberg A more reasonable (but still virtually impossible) question would be for which spaces is every maps which is not a self-homeomorphism generated by retractions. Probably one also wants to put some conditions on the topology so that every bijective cts self-map is a homeomorphism.
Sep 6, 2013 at 15:49 history edited Niemi CC BY-SA 3.0
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Sep 6, 2013 at 15:42 comment added Niemi Fair enough, my motivation is as follows: Take the lattice of all submonoids of the monoid given by all continuous self-maps of a topological space. If am not mistaken, then the atoms in this lattice are precisely the monads generated by one of the (nontrivial) functions that I have listet in my question. Thus, I was interested whether the (lattice-)join of all these gives me the full monoid.
S Sep 6, 2013 at 15:39 history suggested James Cranch CC BY-SA 3.0
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Sep 6, 2013 at 15:35 review Suggested edits
S Sep 6, 2013 at 15:39
Sep 6, 2013 at 15:32 comment added Todd Trimble Where does this problem come from? Given the incomprehensible variety of topological space structures, I'd be inclined to suspect that a characterization over all topological spaces would be hopelessly difficult.
Sep 6, 2013 at 15:26 answer added Benjamin Steinberg timeline score: 6
Sep 6, 2013 at 15:12 history edited Niemi CC BY-SA 3.0
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Sep 6, 2013 at 15:00 answer added James Cranch timeline score: 4
Sep 6, 2013 at 14:53 history asked Niemi CC BY-SA 3.0