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Sep 7, 2013 at 13:51 answer added Misha timeline score: 3
Sep 7, 2013 at 12:05 answer added Neil Hoffman timeline score: 2
Sep 6, 2013 at 7:49 comment added Misha The question still makes no sense to me: Every element of $\pi_1(M,x)$ is represented by infinitely many (isotopy classes of) knots. It is even worse for a pair of knots with the common base-point. Lastly, you have to deal with non-uniqueness of resolution of the crossing of $\alpha$ and $\beta$. I suggest you think more about the question you are trying to ask.
Sep 6, 2013 at 5:27 history edited Zuriel
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Sep 6, 2013 at 5:08 comment added Zuriel You are right. I want to look at the link $a\bigcup b$ and as $a$ and $b$ necessarliy intersect at the base point, we can actually have two ways to create the link $a\bigcup b$ if we shift $b$, say, a little bit from the basepoint so that $a$ and $b$ do not intersect. Or perhaps it is better to simply consider $a\bigcup b$ as a virtual knot?
Sep 6, 2013 at 4:59 comment added Fernando Muro I find strange that you can take them to be disjoint since in order to talk about the fundamental group you have to choose a base point where every path starts and ends.
Sep 6, 2013 at 4:51 history asked Zuriel CC BY-SA 3.0