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Sep 13, 2013 at 17:59 vote accept Will Chen
Sep 7, 2013 at 0:17 comment added Maxime Fortier Bourque The infinite 4-regular tree embeds nicely in the unit disk as the dual graph to the tesselation by regular ideal quarilaterals described by Prof. Eremenko below. This is because the puntured torus is covered by your space $\mathbb{C} \setminus (\mathbb{Z} + i \mathbb{Z})$. Of course, you can lift any deformation-retraction of the punctured-torus onto the wedge of two circles to a deformation-retraction of the unit disk onto the infinite tree.
Sep 6, 2013 at 13:30 comment added Alexandre Eremenko @oxeimon: I understand that $H$ is equivalent to the unit disc. But what your question means: "$H$ deformation retractable to a tree"? Of course the half-plane or the disc is retractable to a tree...
Sep 5, 2013 at 23:49 comment added Dan Petersen The tree in part 2 should look something like this: en.wikipedia.org/wiki/File:H2_tiling_24i-1.png
Sep 5, 2013 at 22:59 comment added Will Chen Alexandre Eremenko: The Riemann mapping theorem shows that the open unit disc is conformally equivalent to the upper half plane.
Sep 5, 2013 at 22:24 comment added Alexandre Eremenko I did not understand the second question. The universal cover of the punctured torus is the open unit disc.
Sep 5, 2013 at 22:20 answer added Alexandre Eremenko timeline score: 12
Sep 5, 2013 at 20:58 comment added Jesse Silliman Ah, sorry, I should have read more carefully.
Sep 5, 2013 at 20:24 history edited Will Chen CC BY-SA 3.0
clarifications in the title
Sep 5, 2013 at 20:24 comment added Will Chen I actually mean $\mathbb{C}$ minus all the lattice points.
Sep 5, 2013 at 19:57 history asked Will Chen CC BY-SA 3.0