Timeline for Integral orthogonal group for indefinite ternary quadratic form
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 3, 2021 at 22:10 | answer | added | Mathieu Dutour Sikiric | timeline score: 1 | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
|
|
| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
|
|
| Sep 6, 2013 at 10:23 | comment | added | Venkataramana | Since the quadratic form represents a rational zero, the integral group is commensurable with $PSL(2,{\mathbb Z})\simeq SO(2,1)({\mathbb Z})$. It would be interesting to see what the congruence subgroup is, I suppose. Otherwise, the "general" answer is that is is a congruence subgroup of the integral modular group. | |
| Sep 5, 2013 at 20:05 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 19 characters in body
|
| Sep 5, 2013 at 19:30 | vote | accept | Will Jagy | ||
| Sep 5, 2013 at 14:57 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 10481 characters in body
|
| Sep 5, 2013 at 8:24 | answer | added | few_reps | timeline score: 7 | |
| Sep 5, 2013 at 7:12 | answer | added | SashaKolpakov | timeline score: 6 | |
| Sep 5, 2013 at 6:10 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 139 characters in body
|
| Sep 5, 2013 at 6:01 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 68 characters in body
|
| Sep 5, 2013 at 5:52 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 250 characters in body
|
| Sep 5, 2013 at 5:29 | history | edited | Will Jagy | CC BY-SA 3.0 |
added 313 characters in body
|
| Sep 5, 2013 at 5:25 | comment | added | Will Jagy | @Noam, for example, the Apollonian group is generated by four matrices, each of which squares to the identity. At least I think they are saying the same thing. | |
| Sep 5, 2013 at 5:21 | comment | added | Will Jagy | @Noam, hi, some description with a subset of these as generators, I would guess no more than about five. I experimented trying to write some of the matrices as products of the most attractive ones, but did not get very far. Thanks for your interest. I'll wait on your reply a bit. | |
| Sep 5, 2013 at 5:19 | comment | added | Noam D. Elkies | Wait, this looked like a good start but what's the question $-$ what do you want to know about this orthogonal group? | |
| Sep 5, 2013 at 5:18 | comment | added | Will Jagy | I'm running out of steam. I had a dental crown first session today, and I'm wiped out and going to bed. Sorry if you stay up later than I do and need clarification of something, I'll need to attend to that tomorrow. Mostly I don't like it when people post a question and walk away, so I thought I would mention it in advance. | |
| Sep 5, 2013 at 5:09 | history | asked | Will Jagy | CC BY-SA 3.0 |