Timeline for Infinite dimensional quotients of L_1 by isomorphic subspaces
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 7, 2013 at 4:35 | comment | added | Bill Johnson | @AmirBahmanNasseri: AFAIK, everything known about $L_1/L_1$ is contained in my paper "Extensions of $c_0$" and the paper of Kalton and Pelczynski on which it is based, which gives only that $L_1/L_1$ must have finite cotype and hence cannot be superreflexive. | |
| Sep 3, 2013 at 17:12 | history | edited | Amir Bahman Nasseri | CC BY-SA 3.0 |
added 401 characters in body
|
| Sep 3, 2013 at 14:26 | history | edited | Amir Bahman Nasseri | CC BY-SA 3.0 |
added 186 characters in body; edited title
|
| Sep 3, 2013 at 5:53 | comment | added | Yemon Choi | @FrançoisG.Dorais I've found two more unregistered accounts of Amir: mathoverflow.net/users/38789/amir-bahman-nasseri and mathoverflow.net/users/38843/amir-bahman-nasseri | |
| Sep 2, 2013 at 20:09 | comment | added | François G. Dorais | Please register one of your accounts and ask to merge your two accounts at mathoverflow.net/contact. | |
| Sep 2, 2013 at 19:49 | comment | added | Yemon Choi | That doesn't answer my question. Almost anyone in research faced with a problem, whatever the level, will have tried to reduce it to a simpler problem, or to prove a weaker case, perhaps consulting other literature. At present all we have here is an interesting question, but if you showed more of your own thoughts then perhaps people here would find it easier to offer helpful suggestions | |
| Sep 2, 2013 at 19:32 | comment | added | Amir Bahman Nasseri | My Indikation is the Folklore | |
| Sep 2, 2013 at 19:19 | comment | added | Yemon Choi | Thanks for the extra detail. You should edit this into your original question (and avoid creating two separate accounts) | |
| Sep 2, 2013 at 19:11 | comment | added | user39474 | My intention is the following Yemon: If the subspace $M$ isomorphic to $L_1(0,1)$ is complemented, then the quotient is clearly non-reflexive. So as we know, there are subspaces isomorphic to $L_1(0,1)$ but not complemented. But what can we say about the reflexivity of this quotient. I asked these questions for research about some questions with regard to tauberian operators. | |
| Sep 2, 2013 at 18:54 | comment | added | Yemon Choi | Also, the title of the question is misleading. It is trivial that there exist non-reflexive quotients of $L^1$, but you are asking for something much more specific | |
| Sep 2, 2013 at 18:52 | comment | added | Yemon Choi | Amir, this is the second question in a row where you ask things without giving an indication of what steps you yourself have tried in order to attack this problem. You also have not given any motivation for this series of questions. | |
| Sep 2, 2013 at 18:31 | history | asked | Amir Bahman Nasseri | CC BY-SA 3.0 |